LeetCode 108.将有序数组转换为二叉搜索树
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https://programmercarl.com/0108.%E5%B0%86%E6%9C%89%E5%BA%8F%E6%95%B0%E7%BB%84%E8%BD%AC%E6%8D%A2%E4%B8%BA%E4%BA%8C%E5%8F%89%E6%90%9C%E7%B4%A2%E6%A0%91.html

视频讲解:https://www.bilibili.com/video/BV1uR4y1X7qL

CPP

/**
 * Definition for a binary tree node.
 * struct TreeNode {
 *     int val;
 *     TreeNode *left;
 *     TreeNode *right;
 *     TreeNode() : val(0), left(nullptr), right(nullptr) {}
 *     TreeNode(int x) : val(x), left(nullptr), right(nullptr) {}
 *     TreeNode(int x, TreeNode *left, TreeNode *right) : val(x), left(left), right(right) {}
 * };
 */
class Solution {
public:
    TreeNode* traversal(vector<int>& nums, int left, int right){
        if(left > right)return nullptr;
        int mid = left + (right - left)/2;
        TreeNode* node = new TreeNode(nums[mid]);
        node->left = traversal(nums, left, mid - 1);
        node->right = traversal(nums, mid + 1, right);
        return node;
    }
    TreeNode* sortedArrayToBST(vector<int>& nums) {
        TreeNode* root = traversal(nums, 0, nums.size() - 1);
        return root;
    }
};
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Source: github.com/k4yt3x/flowerhd
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