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1.还是递归先做第一遍,后续队列在迭代做一次。
CPP
/**
* Definition for a binary tree node.
* struct TreeNode {
* int val;
* TreeNode *left;
* TreeNode *right;
* TreeNode() : val(0), left(nullptr), right(nullptr) {}
* TreeNode(int x) : val(x), left(nullptr), right(nullptr) {}
* TreeNode(int x, TreeNode *left, TreeNode *right) : val(x), left(left), right(right) {}
* };
*/
class Solution {
public:
int getMin(TreeNode *node){
if(node == NULL)return 0;
int leftDepth = getMin(node->left);
int rigthDepth = getMin(node->right);
if(node->left == NULL && node->right != NULL)return 1+rigthDepth;
if(node->right == NULL && node->left != NULL)return 1+leftDepth;
int res = 1 + min(leftDepth,rigthDepth);
return res;
}
int minDepth(TreeNode* root) {
return getMin(root);
}
};